(2x - 1)(2x2 - 3x + 2) Answer by bandgeek1749(3) You can put this solution on YOUR website! |
#=color(green)(6x^3+5x^2-4x+3#
Explanation:
#color(blue)((2x+3))(3x^2−2x+1)#
Here, we need to multiply each term within the first bracket with all three terms of the second bracket.
#=color(blue)((2x))(3x^2−2x+1)+color(blue)((3))(3x^2−2x+1)#
#=6x^3−4x^2+2x+9x^2−6x+3#
Grouping like terms
#=6x^3+9x^2−4x^2+2x−6x+3#
#=6x^3+5x^2-4x+3#
ANSWER:
(i) (3x^2-2x-1)\ by\ (2x^2+x-5)
= (3x^2-2x-1)(2x^2+x-5)
= 3x^2(2x^2+x-5)-2x(2x^2+x-5)-1(2x^2+x-5)
= 6x^4+3x^3-15x^2-4x^3-2x^2+10x-2x^2-x+5
= 6x^4-x^3-19x^2+9x+5
(ii) (2 – 3y – 5y2) by (2y- 1 + 3y2)
= (2-3y-5y^2)\times(2y-1+3y^2)
= 2(2y-1+3y^2)-3y(2y-1+3y^2)-5y^2(2y-1+3y^2)
= 4y-2+6y^2-6y^2+3y-9y^3-10y^3+5y^2-15y^4
= -15y^4-19y^3+5y^2+7y-2
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Multiply 2x^(2)_3x+4 by 3x^(2)...
Updated On: 27-06-2022
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